<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: Quartus / sdc: Constraining I/O ports clocked by an internal clock</title>
	<atom:link href="http://billauer.se/blog/2018/08/quartus-sdc-constraining-pins-derived-clock/feed/" rel="self" type="application/rss+xml" />
	<link>https://billauer.se/blog/2018/08/quartus-sdc-constraining-pins-derived-clock/</link>
	<description>Anything I found worthy to write down.</description>
	<lastBuildDate>Thu, 26 Mar 2026 13:15:15 +0000</lastBuildDate>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	<generator>http://wordpress.org/?v=3.1.2</generator>
	<item>
		<title>By: eli</title>
		<link>https://billauer.se/blog/2018/08/quartus-sdc-constraining-pins-derived-clock/comment-page-1/#comment-1387</link>
		<dc:creator>eli</dc:creator>
		<pubDate>Thu, 13 Dec 2018 07:40:58 +0000</pubDate>
		<guid isPermaLink="false">https://billauer.se/blog/?p=5474#comment-1387</guid>
		<description>Actually, the delays by the PLL and the clock network can be, and usually are, corrected by the PLL itself, as its reference can be set to be the global clock network.</description>
		<content:encoded><![CDATA[<p>Actually, the delays by the PLL and the clock network can be, and usually are, corrected by the PLL itself, as its reference can be set to be the global clock network.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Kelly lindseth</title>
		<link>https://billauer.se/blog/2018/08/quartus-sdc-constraining-pins-derived-clock/comment-page-1/#comment-1386</link>
		<dc:creator>Kelly lindseth</dc:creator>
		<pubDate>Thu, 13 Dec 2018 06:41:03 +0000</pubDate>
		<guid isPermaLink="false">https://billauer.se/blog/?p=5474#comment-1386</guid>
		<description>Is this necessary if your pll is multiplying by a power of two, such as 4 let’s say?

It would seem so, because the pll is internal and has a bunch of delays that get added into the calculation incorrectly apparently.</description>
		<content:encoded><![CDATA[<p>Is this necessary if your pll is multiplying by a power of two, such as 4 let’s say?</p>
<p>It would seem so, because the pll is internal and has a bunch of delays that get added into the calculation incorrectly apparently.</p>
]]></content:encoded>
	</item>
</channel>
</rss>
